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123456789101112131415161718192021222324252627arr=[]number=1sum=0for i in range(1,502): arr_temp=[] count=((i*2-1)-1)*4 if(count==0): count=1 for j in range(0,count): arr_temp.append(number) number=number+1 arr.append(arr_temp)for i in range(1,502): matrix=i*2-1 if(matrix==1): sum=sum+1 continue index1=matrix-2 index2=index1+matrix-1 index3=index2+matrix-1 index4=index3+matrix-1 sum=sum+arr[i-1][..

12345678910111213141516number=1sum_result=0sum=0for a in range(1,100): for b in range(1,100): for pow in range(0,b): number=number*a length=len(str(number)) for index in range(0,length): sum=sum+(int)(str(number)[index]) if(sum_result

123456789101112count=2a=1b=1while(1): count=count+1 c=a+b if(len(str(c))==1000): break a=b b=cprint(count)#반환 시간 : 0.1scs 피보나치 수열을 구하는 코드를 작성하였고 길이가 1000이 될 때 반복문을 빠져나오게 하였다.